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快速掌握简单c++游戏代码
2023-07-13 11:30:53 深夜i     --     --
C++ 游戏 代码 简单 快速掌握

C++是一门广泛使用的高级程序设计语言,可以用于开发各种类型的软件,包括电子游戏。如果你对C++编程感兴趣,下面是一些简单的游戏代码,可让你快速掌握C++游戏开发。

1、"猜数字"游戏。

以下是一个简单的猜数字游戏示例代码。首先,计算机会随机生成1到100之间的一个数字。玩家需要在10次机会内猜出这个数字。

#include

#include

#include

using namespace std;

int main()

{

  srand(static_cast (time(0)));

  int secretNumber = rand() % 100 + 1;

  int tries = 0;

  int guess;

  do

  {

    cout << "Enter guess: ";

    cin >> guess;

    tries++;

    if (guess > secretNumber)

      cout << "Too high!" << endl;

    else if (guess < secretNumber)

      cout << "Too low!" << endl;

    else

      cout << "You win!" << endl;

  } while (guess != secretNumber && tries < 10);

  if (tries == 10)

    cout << "You lose!" << endl;

  return 0;

}

2、"井字游戏"。

以下是一个简单的井字游戏示例代码。这个游戏由两个玩家轮流放置X或O,目标是在3x3的棋盘上形成3个连续的符号。

#include

using namespace std;

char board[3][3] = {'1', '6', '9'};

char currentPlayer = 'X';

void drawBoard()

{

  cout << "-------------" << endl;

  for (int i = 0; i < 3; i++)

  {

    cout << "| ";

    for (int j = 0; j < 3; j++)

    {

      cout << board[i][j] << " |

      cout << board[i][j] << " | ";

    cout << endl << "-------------" << endl;

  }

}

bool hasWon(char player)

{

  for (int i = 0; i < 3; i++)

  {

    if (board[i][0] == player && board[i][1] == player && board[i][2] == player)

      return true;

    if (board[0][i] == player && board[1][i] == player && board[2][i] == player)

      return true;

  }

  if (board[0][0] == player && board[1][1] == player && board[2][2] == player)

    return true;

  if (board[0][2] == player && board[1][1] == player && board[2][0] == player)

    return true;

  return false;

}

bool isDraw()

{

  for (int i = 0; i < 3; i++)

  {

    for (int j = 0; j < 3; j++)

    {

      if (board[i][j] != 'X' && board[i][j] != 'O')

        return false;

    }

  }

  return true;

}

int main()

{

  drawBoard();

  while (!hasWon('X') && !hasWon('O') && !isDraw())

  {

    int row, col;

    cout << currentPlayer << " turn. Enter row and column (1-3): ";

    cin >> row >> col;

    if (board[row-1][col-1] != 'X' && board[row-1][col-1] != 'O')

    {

      board[row-1][col-1] = currentPlayer;

      if (currentPlayer == 'X')

        currentPlayer = 'O';

      else

        currentPlayer = 'X';

    }

    else

      cout << "That location is already occupied. Try again." << endl;

    drawBoard();

  }

  if (hasWon('X'))

    cout << "X wins!" << endl;

  else if (hasWon('O'))

    cout << "O wins!" << endl;

  else

    cout << "It's a draw!" << endl;

  return 0;

}

在完成这些简单的游戏示例代码之后,你可能会想尝试一些更复杂的程序或游戏。C++语言具有强大的功能和灵活性,因此可以用来开发各种各样的游戏,从简单的文本游戏到复杂的图形游戏。如果你想深入了解C++编程,可以查阅相关书籍、教程或参加编程培训课程。

  
  

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