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简单易学:C++贪吃蛇代码双人对战
2023-07-01 03:20:12 深夜i     --     --
C++ 贪吃蛇代码 双人对战 简单易学 游戏编程

贪吃蛇是一款经典的小游戏,让人们在怀旧的同时也能感受到游戏的愉悦。而今天我们将介绍一种简单易学的C++贪吃蛇代码,同时还支持双人对战。

首先,我们需要了解一些基本概念。贪吃蛇游戏的核心是在一个空间内实现蛇的移动,同时吃掉食物加分。当蛇碰到边界或自己的身体时,游戏结束。而双人对战则加入了两条蛇之间互相攻击的元素。

下面是一份简单的C++代码,可供参考:


#include <iostream>

#include <conio.h>

#include <windows.h>

using namespace std;

const int n = 25, m = 50;

int x1, y1, dx1, dy1, len1 = 2, score1 = 0, x2, y2, dx2, dy2, len2 = 2, score2 = 0, speed = 100;

bool gameover1 = false, gameover2 = false;

char a[n][m];

void init1()

{

  x1 = n / 2;

  y1 = m / 3;

  dx1 = 0;

  dy1 = 1;

  for (int i = 0; i < n; i++)

  {

    for (int j = 0; j < m; j++)

    {

      if (i == 0 || i == n - 1 || j == 0 || j == m - 1)

        a[i][j] = '*';

      else

        a[i][j] = ' ';

    }

  }

  a[x1][y1] = '#';

  a[x1][y1 + 1] = '#';

}

void init2()

{

  x2 = n / 2;

  y2 = m / 3 * 2;

  dx2 = 0;

  dy2 = -1;

  a[x2][y2] = '#';

  a[x2][y2 - 1] = '#';

}

void draw()

{

  system("cls");

  for (int i = 0; i < n; i++)

  {

    for (int j = 0; j < m; j++)

    {

      cout << a[i][j];

    }

    cout << endl;

  }

  cout << "Score1: " << score1 << endl << "Score2: " << score2 << endl;

}

void input()

{

  if (_kbhit())

  {

    char ch = _getch();

    if (ch == 'a')

    {

      if (dy1 != 1)

      

        dx1 = 0;

        dy1 = -1;

      

    }

    if (ch == 'd')

    {

      if (dy1 != -1)

      

        dx1 = 0;

        dy1 = 1;

      

    }

    if (ch == 'w')

    {

      if (dx1 != 1)

      

        dx1 = -1;

        dy1 = 0;

      

    }

    if (ch == 's')

    {

      if (dx1 != -1)

      

        dx1 = 1;

        dy1 = 0;

      

    }

    if (ch == 'j')

    {

      if (dy2 != 1)

      

        dx2 = 0;

        dy2 = -1;

      

    }

    if (ch == 'l')

    {

      if (dy2 != -1)

      

        dx2 = 0;

        dy2 = 1;

      

    }

    if (ch == 'i')

    {

      if (dx2 != 1)

      

        dx2 = -1;

        dy2 = 0;

      

    }

    if (ch == 'k')

    {

      if (dx2 != -1)

      

        dx2 = 1;

        dy2 = 0;

      

    }

    if (ch == 'q')

      gameover1 = true;

    if (ch == 'p')

      gameover2 = true;

  }

}

void logic()

{

  int nx1 = x1 + dx1;

  int ny1 = y1 + dy1;

  int nx2 = x2 + dx2;

  int ny2 = y2 + dy2;

  if (nx1 >= n - 1 || nx1 < 0 || ny1 >= m - 1 || ny1 < 0 || a[nx1][ny1] == '#')

    gameover1 = true;

  if (nx2 >= n - 1 || nx2 < 0 || ny2 >= m - 1 || ny2 < 0 || a[nx2][ny2] == '#')

    gameover2 = true;

  if (a[nx1][ny1] == '$')

  {

    score1++;

    len1++;

    speed = max(speed - 10, 50);

    a[nx1][ny1] = '#';

    if (nx2 == nx1 && ny2 == ny1)

    {

      score2--;

      if (len2 > 2)

      {

        len2--;

        for (int i = 0; i < n; i++)

        {

          for (int j = 0; j < m; j++)

          {

            if (a[i][j] == '*' || a[i][j] == ' ' || a[i][j] == '$')

              continue;

            if (a[i][j] == '#')

              a[i][j] = ' ';

          }

        }

        int t = len2;

        int x = x2;

        int y = y2 - 1;

        while (t--)

        {

          a[x][y] = '#';

          y--;

        }

      }

      else

      

        gameover2 = true;

      

    }

  }

  else

  {

    a[x1 + dx1 * (len1 - 1)][y1 + dy1 * (len1 - 1)] = ' ';

    for (int i = len1 - 1; i > 0; i--)

    {

      a[x1 + dx1 * i][y1 + dy1 * i] = a[x1 + dx1 * (i - 1)][y1 + dy1 * (i - 1)];

    }

    a[x1][y1] = ' ';

    x1 = nx1;

    y1 = ny1;

    a[x1][y1] = '#';

  }

  if (a[nx2][ny2] == '$')

  {

    score2++;

    len2++;

    speed = max(speed - 10, 50);

    a[nx2][ny2] = '#';

    if (nx2 == nx1 && ny2 == ny1)

    {

      score1--;

      if (len1 > 2)

      {

        len1--;

        for (int i = 0; i < n; i++)

        {

          for (int j = 0; j < m; j++)

          {

            if (a[i][j] == '*' || a[i][j] == ' ' || a[i][j] == '$')

              continue;

            if (a[i][j] == '#')

              a[i][j] = ' ';

          }

        }

        int t = len1;

        int x = x1;

        int y = y1 + 1;

        while (t--)

        {

          a[x][y] = '#';

          y++;

        }

      }

      else

      

        gameover1 = true;

      

    }

  }

  else

  {

    a[x2 + dx2 * (len2 - 1)][y2 + dy2 * (len2 - 1)] = ' ';

    for (int i = len2 - 1; i > 0; i--)

    {

      a[x2 + dx2 * i][y2 + dy2 * i] = a[x2 + dx2 * (i - 1)][y2 + dy2 * (i - 1)];

    }

    a[x2][y2] = ' ';

    x2 = nx2;

    y2 = ny2;

    a[x2][y2] = '#';

  }

  Sleep(speed);

}

void run()

{

  while (!gameover1 && !gameover2)

  {

    draw();

    input();

    logic();

  }

  if (gameover1)

    cout << "Player1 lost!" << endl;

  if (gameover2)

    cout << "Player2 lost!" << endl;

}

int main()

{

  init1();

  init2();

  run();

  return 0;

}

该代码实现了一个25x50的游戏空间,同时在游戏开始时分别初始化了两条蛇,支持双人游戏。通过键盘输入控制两条蛇的移动并在相应条件下进行判断得分。整个游戏运行的逻辑在run函数中。同时,通过不断地调整speed变量的值来实现游戏节奏。

总的来说,这份贪吃蛇代码相对较为简单,适合初学者学习和实践,不需要过多的编程经验。希望读者们通过学习该代码加深对C++的了解,同时也能在游戏的快乐中度过时光。

  
  

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